F. H. Richardson's bluebook of projection (1935)

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ELECTRICAL CONDUC WRS 67 21 XL Formula No. 1 : — R. A Formula No. 2 : e = L X R 21 X I X L Formula No. 3 : e = A 21 X I XL Formula No. 4 : A = e Formula No. 5: When voltage drop is expressed in percentages, Formula No. 5 may be used to determine the wire cross-section area necessary to provide the required voltage drop: 2100 X I X L = A or cross-section in circular mils. EXP (19) Suppose a circuit is needed with a one-way length of 60 feet to carry 100 amperes with a 3 percent voltage drop, the voltage of the circuit being 110. Substituting figures in place of the letters we have 2100 X 100 X 60 = 38,181 circular mils. 110X3 No. 5 wire being too small (see Table No. 2), we would have to employ No. 4, which would be a little too large and would not give quite the 3 percent drop. Measuring Wires (20) Cross-section area of wires is expressed in circular mils. For conductors other than round in form the square mil is used. A circle 1/1000 of an inch in diameter is called a "circular mil," abbreviated to CM. The cross-section area means CM. area of the end of the wire. (21) Crosssection area of round wires is equal to the square of the wire diameter expressed in CM. To square the diameter of a wire, multiply its diameter in circular mils by itself. (22) The capacity of any round wire of commercial