We use Optical Character Recognition (OCR) during our scanning and processing workflow to make the content of each page searchable. You can view the automatically generated text below as well as copy and paste individual pieces of text to quote in your own work.
Text recognition is never 100% accurate. Many parts of the scanned page may not be reflected in the OCR text output, including: images, page layout, certain fonts or handwriting.
ELECTRICAL ACTION 11
alternately in this case) are attached. Between these wires lamps L are connected. (24) Examining this diagram it is clear that any current generated may flowthrough coil AB into one of the brushes KJ, on into one of the wires and through lamps L into the other wire. producing light in the lamps of course. We then have a complete, or "closed" circuit in Fig. 1.
1 low Generation Carries On
(25) Now if we rotate coil AB by means of crank G in the direction of arrow O, coil side A will pass down and side B upward through the magnetic field, cutting across lines of magnetic force. In so doing the action will (see law previously quoted) generate an electric impulse (current) which will, under the conditions named, flow through the entire closed circuit in the direction indicated by arrows M. P.
All Armatures Generate Alternating Current
(26) Let us now advance a step: in Fig. 1 it is assumed that crank G rotates in direction O. Under that condition current generated will flow toward brush K and wire E. As the coil now lies, it is in the very strongest part of the magnetic field. When it is rotated, one side rises and the other lowers gradually, both nol only passing out of the strongest part of the field, but moving more and more in the direction of the lines of magnetic force, hence cutting across less and less and finally none of them. Analyzing this action we see that gradually (the action becomes really very fast) the voltage and consequently the current generated grow .weaker, until finally both cease entirely. (27) However since the coil continues to move, side B immediately starts downward and side A upward, so that both again start cutting lines of magnetic force, but in an opposite direction to that of the preceding half-revolution.
Since the current flows in one direction with relation to the magnetic field, it is evident that the current gener ated in this second half-revolution will not flow into brush C, but instead into brush D, and thus the direction