F. H. Richardson's bluebook of projection (1935)

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436 RICHARDSON'S BLUEBOOK OF PROJECTION metic will see instantly that the following must also be true : I = E-f-R and: R = E--i The reader who may have forgotten so much of his arithmetic that he doesn't see why the two other forms of Ohm's Law must of necessity follow or result from the first, may ask himself these questions : If 60 volts force 10 amperes through 6 ohms, is it not obvious that 6 equals 60 divided by 10, and therefore that the resistance must equal the voltage divided by the current ? In the same way, is it not true that the current (10 amperes) must equal the voltage divided by the resistance (60 divided by 6) ? The result arrived at will be the same with any other set of numbers. Try it. Write the first form of Ohm's Law, E = I X R. Chose any numbers at all for I and for R. Multiply them together to find the E of that particular circuit, and it will be found that I always equals E over R and that R always equals E over I. No matter what numbers are chosen, the result will always balance. (10) If one volt is the force necessary to drive one ampere through one ohm, then all three forms of Ohm's Law must be true by arithmetical necessity. It is by "fooling" Ohm's Law that an amplifying tube amplifies sound currents. How this is done will become plain a little further on when certain other electrical fundamentals have been considered. 1 £ ° /XR ^/ Y VJJL^i