Journal of the Society of Motion Picture Engineers (1930-1949)

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1949 ARC SPOTLIGHT 415 Now we wish to find the distance d between the two lenses, so by observation (Fig. 5) Substituting (2) and (3) we obtain !/„/„ d = /2 d + ui = Mi5 2 -ft (4) (5) Therefore for any distance u\ of the small lens, and a known projection distance F2, we can readily calculate the position of the large lens to obtain a sharp, clear-cut spot. s v2 Fig. 5 — Lens optical system. F2 t/2 focal length of small lens. A object distance for small lens. D image distance for small lens. S focal length of large lens. / object distance for large lens. R aperture diameter, distance between lenses, diameter of projected spot, virtual image, reflector. image distance for large lens. It is evident that the small lens creates a virtual image of the aperture. The large lens focuses on this virtual image and projects it to the desired location. Table I shows the various distances of the large lens from the aperture as the small lens distance is varied. For these calculations the projected throw (F2) is 60 feet. TABLE I u\, Inches d + Ui, Inches ui, Inches d + ui, Inches 0 18.47 1.50 16.22 0.25 18.44 1.75 14.39 0.50 18.34 2.00 10.47 0.75 18.15 2.125 6.43 1.00 17.80 2.160 4.75 1.25 17.22 2.1875 3.12