Motion picture handbook; a guide for managers and operators of motion picture theatres ([c1916])

Page scan 00048 from Motion picture handbook; a guide for managers and operators of motion picture theatres

Record Details:

Title:
Motion picture handbook; a guide for managers and operators of motion picture theatres
Date:
[c1916]
Publisher:
New York City, The Moving Picture World
Volume:
Motion picture handbook; a guide for managers and operators of motion picture theatres
Leaf #:
00048
Language:
English
Collection:
Books
Format:
Books
Contributor:
University of California Libraries
Sponsor:
MSN
Coordinator:
Media History Digital Library
Date Added:
July 19, 2022
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FOR MANAGERS AND OPERATORS 29 as 50/100, 5/10, or 1/2. The rule .is to count the figures or ciphers to the right of the decimal point in the number being divided, and then, beginning at the last figure of the result, count an equal number, and place the decimal to the left of the last figure counted. If there are not enough figures in the result to do this, then add ciphers to the left. E When dealing with formulas, — means that the quantity C represented by E is to be divided by the quantity represented by C, E being the voltage and C amperes. If there be two or more quantities above or below the line, with no sign between them, it means they are to be multiplied together, thus: E means that E (volts) is to be divided by C (amperes) C R E — 15 multiplied by R (ohms), means that after 15 has been C subtracted from the quantity represented by E (volts) it is to be divided by the quantity represented by C (amperes). The student will be greatly benefited if he will practice writing out formulas of this kind in letters, substituting quantities in figures and working them out. Ohms law sets forth the fact that the number of amperes flowing are equal to the voltage divided by the resistance in E ohms. We, therefore have — = C, or, in other words, volts R divided by ohms equals amperes. It then follows that if E — = C, C multiplied by R must equal E. It also follows that R E • — = R. It works out as follows: We know that the ordinary C 110-volt 16 c.p. carbon filament incandescent lamp requires approximately one-half ampere of current to bring it up to candle power. What is its resistance? Using the formula E 110 volts — = R, substituting figures, we have — = 220, C .5 of an ampere the number of ohms resistance in the filament of the lamp.