Richardson's handbook of projection (1927)

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424 HANDBOOK OF PROJECTION FOR In other words, instead of 2-ohms resistance opposed to th3 voltage, as would be the case if we had but a single rheostat, 4-ohms resistance is opposed. Disregarding the resistance of the arc, if the supply current were 110 volts and we had but a single 2-ohm resistance rheostat connected in there would be a resultant current flow of 110 -* 2 = 55 amperes. ffccr-s r c?o#/y /p//fosr/?r + Figure 134. If we now connect another 2-ohm rheostat in series as per Fig. 134, we will have 4 ohms opposed to the current, and, again disregarding the arc resistance, we would as a result have 110 -* 4 = 27.5+ amperes current flow. Please understand clearly that this would not be the result of the connection shown in Fig. 134, because in addition to the 4 ohms opposed by the rheostats there would be the resistance of the arc added thereto. In the above we are merely showing you the way the thing operates — not working out accurate results. The actual total resistance of such a combination, including the arc, would be about 5 ohms, hence the actual current flow 110 -* 5 = 22 amperes. MULTIPLE CONNECTION.— The multiple connection is one which puzzles many, yet it is a very simple matter, once one gets a clear idea of the principles involved. Fig. 135 is the diagrammatic representation of a water main, A, connected to the supply pipe B of a motor by means of two small pipes in which valves C-D are installed. \ t 4 & "Blrtrr** Aforo*?. —+ f Figure 135.